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\sqrt [3] { (a^2)^6}
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Updated on: 21 Jan 2019, 10:41
Updated on: 21 Jan 2019, 10:41
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91% (00:23) correct
8% (01:40) wrong based on 34 sessions
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\(\sqrt [3] { (a^2)^6}\)
A) \(a^2\)
B) \(a^4\)
C) \(a^5\)
D) \(a^9\)
E) \(a^11\)
A) \(a^2\)
B) \(a^4\)
C) \(a^5\)
D) \(a^9\)
E) \(a^11\)
Originally posted by CAMANISHPARMAR on 21 Jan 2019, 03:05.
Last edited by Carcass on 21 Jan 2019, 10:41, edited 4 times in total.
Last edited by Carcass on 21 Jan 2019, 10:41, edited 4 times in total.
Edited by Carcass
Re: \sqrt [3] { (a^2)^6}
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21 Jan 2019, 13:38
21 Jan 2019, 13:38
Expert Reply
Inside the root we do have \(a^{12}\) (because we multiply the two exponents )
Then we eliminate the root doing the exponents as a fraction
\(a^ {\frac{12}{3}} = a^4\)
B is the answer
Then we eliminate the root doing the exponents as a fraction
\(a^ {\frac{12}{3}} = a^4\)
B is the answer
gmatclubot
Re: \sqrt [3] { (a^2)^6} [#permalink]
21 Jan 2019, 13:38
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