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(sqrt of 2 - sqrt of 3 )^2
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15 May 2021, 01:24
15 May 2021, 01:24
Expert Reply
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\(( \sqrt{2}-\sqrt{3})^2 = \)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
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(sqrt of 2 - sqrt of 3 )^2
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15 May 2021, 22:38
15 May 2021, 22:38
Carcass wrote:
\(( \sqrt{2}-\sqrt{3})^2 = \)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
Are you sure this is a hard level question?
\((\sqrt{2}-\sqrt{3})^2\)
\(\sqrt{2}^2 + \sqrt{3}^2 - 2(\sqrt{2})(\sqrt{3})\)
\(2 + 3 - 2\sqrt{6}\)
\(5 - 2\sqrt{6}\)
Hence, option C
Re: (sqrt of 2 - sqrt of 3 )^2
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15 May 2021, 22:52
15 May 2021, 22:52
Expert Reply
KarunMendiratta wrote:
Carcass wrote:
\(( \sqrt{2}-\sqrt{3})^2 = \)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
A. \(1\)
B. \(5-2 \sqrt{3}\)
C. \(5-2 \sqrt{6}
\)
D. \(1-\sqrt{6}\)
E. \(1-2 \sqrt{6}\)
Are you sure this is a hard level question?
\((\sqrt{2}-\sqrt{3})^2\)
\(\sqrt{2}^2 + \sqrt{3}^2 - 2(\sqrt{2})(\sqrt{3})\)
\(2 + 3 - 2\sqrt{6}\)
\(5 - 2\sqrt{6}\)
Hence, option C
No.
But the stage is in between.
Also see always the students' standing point NOT yours.
You are a tutor. And pretty good I would say KarunMendiratta
