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\sqrt12.5 + \sqrt12.5
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16 Apr 2019, 01:28
16 Apr 2019, 01:28
Expert Reply
00:00
Question Stats:
83% (00:25) correct
16% (00:07) wrong based on 61 sessions
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Quantity A |
Quantity B |
\(\sqrt{12.5} + \sqrt{12.5}\) |
\(\sqrt{25}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: \sqrt12.5 + \sqrt12.5
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16 Apr 2019, 05:33
16 Apr 2019, 05:33
2
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Carcass wrote:
Quantity A |
Quantity B |
\(\sqrt{12.5} + \sqrt{12.5}\) |
\(\sqrt{25}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
√9 = 3
√16 = 4
Since 12.5 is BETWEEN 9 and 16, √12.5 must be between 3 and 4
We can say that √12.5 = 3.something
We get:
QUANTITY A: 3.something + 3.something
QUANTITY B: 5
We can see that Quantity A is greater.
Answer: A
Cheers,
Brent
Re: \sqrt12.5 + \sqrt12.5
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02 May 2019, 01:41
02 May 2019, 01:41
1
The solution given is wrong as it is clearly evident that the A= 2*sqrt(12.5) which is 7 and B=5.
The answer should be A.
The answer should be A.
