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\sqrta^2+39=8

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Carcass
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\sqrta^2+39=8 [#permalink] New post   28 Sep 2019, 09:53
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\(\sqrt{a^2+39}=8\)

Quantity A
Quantity B
a
4


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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D
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GreenlightTestPrep
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Re: \sqrta^2+39=8 [#permalink] New post   29 Sep 2019, 05:20
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Carcass wrote:
\(\sqrt{a^2+39}=8\)

Quantity A
Quantity B
a
4





Take: \(\sqrt{a^2+39}=8\)

Square both sides to get: \(a^2+39=64\)

Subtract 39 from both sides to get: \(a^2=25\)

So, EITHER \(a=5\) OR \(a=-5\)

If \(a=5\), then Quantity A is greater
If \(a=-5\), then Quantity B is greater

Answer: D

Cheers,
Brent
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Re: \sqrta^2+39=8 [#permalink]
29 Sep 2019, 05:20
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