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sqrta^2+39=8
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22 Feb 2024, 01:39
22 Feb 2024, 01:39
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Question Stats:
66% (00:34) correct
33% (00:31) wrong based on 6 sessions
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\(\sqrt{a^2+39}=8\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
a |
4 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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sqrta^2+39=8
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22 Feb 2024, 12:35
22 Feb 2024, 12:35
1
\(\sqrt{a^2+39} = 8\)
Square both sides:
\(a^2+39 = 64\)
\(a^2 = 25\)
a = -5 and 5
Since -5 < 4 and 5 > 4, the relationship cannot be determined.
Square both sides:
\(a^2+39 = 64\)
\(a^2 = 25\)
a = -5 and 5
Since -5 < 4 and 5 > 4, the relationship cannot be determined.
gmatclubot
sqrta^2+39=8 [#permalink]
22 Feb 2024, 12:35
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