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Sum of the exterior angles
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08 Jan 2018, 14:19
08 Jan 2018, 14:19
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Question Stats:
45% (00:38) correct
54% (00:43) wrong based on 84 sessions
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Quantity A |
Quantity B |
Sum of the exterior angles in a regular hexagon |
720 degrees |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudo for the right answer and explanation.
Re: Sum of the exterior angles
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10 Jan 2018, 01:19
10 Jan 2018, 01:19
1
So let's calculate the interior angle first.
(N-2)180 = 4*180 = 720.
Since the interio angles all egal to 720 it must be true that the extorior are greater than it.
Or what we can do is to determine one angle = 120 angles and draw a circle around all the angles. The area of the exterior angle will then equal 240 and we just add those 6 times.
Answer A
(N-2)180 = 4*180 = 720.
Since the interio angles all egal to 720 it must be true that the extorior are greater than it.
Or what we can do is to determine one angle = 120 angles and draw a circle around all the angles. The area of the exterior angle will then equal 240 and we just add those 6 times.
Answer A
Re: Sum of the exterior angles
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10 Jan 2018, 01:24
10 Jan 2018, 01:24
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for a hexagon total sides =6
sum of all interior angle of a regular polygon = (n-2)180
for 6 sides this is 4*180 = 720 degree
measure of 1 internal angle=720/6 = 120 degree
Any 1 of the 6 vertex can be extended to form a straight line
Straight angle =180 degree. This leaves us with 180-120= 60 degree for a single external angle
60*6=360 degree = sum of exterior angles (B)
sum of all interior angle of a regular polygon = (n-2)180
for 6 sides this is 4*180 = 720 degree
measure of 1 internal angle=720/6 = 120 degree
Any 1 of the 6 vertex can be extended to form a straight line
Straight angle =180 degree. This leaves us with 180-120= 60 degree for a single external angle
60*6=360 degree = sum of exterior angles (B)
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