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Suppose D is the midpoint of and E is the midpoint of If triangle DE
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30 May 2022, 03:47
30 May 2022, 03:47
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58% (01:47) correct
41% (02:16) wrong based on 17 sessions
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Suppose D is the midpoint of \(\overline{AC}\) and E is the midpoint of \(\overline{BC}\) If triangle DEC has an area of 8 square inches, what is the area of triangle ABC ?
12
16
24
32
64
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: Suppose D is the midpoint of and E is the midpoint of If triangle DE
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08 Jun 2022, 09:52
08 Jun 2022, 09:52
1
area of the small triangle =
8=bh/2 ; 16=bh ;
thus, bh must equal (4,4) or (8,2)
since the sides of the small triangle are the midpoint of the larger one,
area of the larger triangle=
x=2b2h/2 ; 2x=2b2h ;
we can plug in either possible value of the sides of the smaller triangle.
2x=2(4)*2(4); 2x=64; x=32. Area of the larger triangle is 32,
thus D is the answer
8=bh/2 ; 16=bh ;
thus, bh must equal (4,4) or (8,2)
since the sides of the small triangle are the midpoint of the larger one,
area of the larger triangle=
x=2b2h/2 ; 2x=2b2h ;
we can plug in either possible value of the sides of the smaller triangle.
2x=2(4)*2(4); 2x=64; x=32. Area of the larger triangle is 32,
thus D is the answer
Re: Suppose D is the midpoint of and E is the midpoint of If triangle DE
[#permalink]
27 Jul 2022, 18:58
27 Jul 2022, 18:58
piorachid wrote:
area of the small triangle =
8=bh/2 ; 16=bh ;
thus, bh must equal (4,4) or (8,2)
since the sides of the small triangle are the midpoint of the larger one,
area of the larger triangle=
x=2b2h/2 ; 2x=2b2h ;
we can plug in either possible value of the sides of the smaller triangle.
2x=2(4)*2(4); 2x=64; x=32. Area of the larger triangle is 32,
thus D is the answer
8=bh/2 ; 16=bh ;
thus, bh must equal (4,4) or (8,2)
since the sides of the small triangle are the midpoint of the larger one,
area of the larger triangle=
x=2b2h/2 ; 2x=2b2h ;
we can plug in either possible value of the sides of the smaller triangle.
2x=2(4)*2(4); 2x=64; x=32. Area of the larger triangle is 32,
thus D is the answer
Thank you
