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Telephone Company X's monthly charge for long-distance telephone calls
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02 Apr 2021, 05:06
02 Apr 2021, 05:06
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Question Stats:
90% (01:38) correct
10% (01:55) wrong based on 10 sessions
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Telephone Company X's monthly charge for long-distance telephone calls is $1.95 plus $0.10 per minute, whereas Telephone Company Y's monthly charge is $5.95 plus $0.08 per minute. For what total number of minutes of long-distance calls per month would the monthly charge for the two companies be the same?
A. 100
B. 120
C. 150
D. 180
E. 200
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 100
B. 120
C. 150
D. 180
E. 200
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: Telephone Company X's monthly charge for long-distance telephone calls
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02 Apr 2021, 05:39
02 Apr 2021, 05:39
1
Carcass wrote:
Telephone Company X's monthly charge for long-distance telephone calls is $1.95 plus $0.10 per minute, whereas Telephone Company Y's monthly charge is $5.95 plus $0.08 per minute. For what total number of minutes of long-distance calls per month would the monthly charge for the two companies be the same?
A. 100
B. 120
C. 150
D. 180
E. 200
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 100
B. 120
C. 150
D. 180
E. 200
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Let x = the total number of minutes of long-distance calls
Telephone Company X's monthly charge for long-distance telephone calls is $1.95 plus $0.10 per minute
So, TOTAL charge = $1.95 + $0.10(x)
Telephone Company Y's monthly charge is $5.95 plus $0.08 per minute
TOTAL charge = $5.95 + $0.08(x)
For what total number of minutes of long-distance calls per month would the monthly charge for the two companies be the same?
We want to satisfy the equation $1.95 + $0.10(x) = $5.95 + $0.08(x)
Subtract 1.95 from both sides to get: 0.1x = 4 + 0.08x
Subtract 0.08x from both sides to get: 0.02x = 4
So, x = 4/0.02
= 400/2
= 200
Answer: E
Cheers,
Brent
gmatclubot
Re: Telephone Company X's monthly charge for long-distance telephone calls [#permalink]
02 Apr 2021, 05:39
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