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The admission price per child at a certain
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19 Jul 2021, 07:44
19 Jul 2021, 07:44
Expert Reply
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Question Stats:
87% (01:11) correct
12% (00:53) wrong based on 8 sessions
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The admission price per child at a certain amusement park is \(\frac{7}{12}\) of the admission price per adult. If the admission price for 4 adults and 6 children is $112.50, what is the admission price per adult?
(A) $15.00
(B) $13.50
(C) $12.75
(D) $11.25
(E) $8.75
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) $15.00
(B) $13.50
(C) $12.75
(D) $11.25
(E) $8.75
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: The admission price per child at a certain
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19 Jul 2021, 07:55
19 Jul 2021, 07:55
Let's assume:
For adults, prices \(= 12x\) so
for child, prices \(= 7x\)
The admission price for 4 adults and 6 children is $112.50.
\(48x + 42x = 112.50\)
\(90x = 112.50\)
\(x = 1.25\)
Price for adult \(= 12x = 12*1.25 = 15\)
Answer A
For adults, prices \(= 12x\) so
for child, prices \(= 7x\)
The admission price for 4 adults and 6 children is $112.50.
\(48x + 42x = 112.50\)
\(90x = 112.50\)
\(x = 1.25\)
Price for adult \(= 12x = 12*1.25 = 15\)
Answer A
Re: The admission price per child at a certain
[#permalink]
20 Jul 2021, 04:02
20 Jul 2021, 04:02
1
prices per:
children = c
adult = a
c=7/12 a
other equation:
4a + 6c = 112.5
4a + 6(7/12)a = 112.5
4a+7/2a=112.5
15/2 a = 112.5
a = 225/15
a=15 -----(A)
children = c
adult = a
c=7/12 a
other equation:
4a + 6c = 112.5
4a + 6(7/12)a = 112.5
4a+7/2a=112.5
15/2 a = 112.5
a = 225/15
a=15 -----(A)
