Re: The Arc between region A and B is a quarter circLe. The Triangle
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04 May 2024, 10:44
This problem asks you to interpret a geometric drawing in order to determine the relationship between the labeled regions. From the given information you can deduce that the diagram is a square with a diagonal and quarter circle arc overlaid. From this information you can calculate the relative size of the regions.
Region A consists of the quarter circle minus the unlabeled triangle. And since we know that the quarter circle is inscribed in a square this makes the formula for region A:
Area A = Area of Quarter Circle - Area of Triangle
Region B consists of the area of the square minus the quarter circle:
Area 8 = Area of Square - Area of Quarter Circle
You now set up the inequality: Area of Quarter Circle - Area of Triangle ? Area of Square - Area of Quarter Circle If we label each side of the square r we can now insert the formulas for the respective areas:
\(\frac{1}{4} \pi r^2-\frac{1}{2} r^2 ? r^2-\frac{1}{4} \pi r^2\)
Solve
\(2 \pi ? 6\)
\(6.28 >6
\)
A is the answer