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The area of a square region with a perimeter equal to the perimeter of
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02 Oct 2025, 08:30
02 Oct 2025, 08:30
Expert Reply
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Question Stats:
46% (00:34) correct
53% (01:10) wrong based on 15 sessions
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Quantity A |
Quantity B |
The area of a square region with a perimeter equal to the perimeter of rectangular region $A D F C$ |
81 |
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Re: The area of a square region with a perimeter equal to the perimeter of
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01 Nov 2025, 13:55
01 Nov 2025, 13:55
Expert Reply
We must first determine the total perimeter of the rectangle, then divide this amount by 4 (because a square has four equal sides) to find the sides of the square.
The perimeter of a rectangle is $\(2(l+w)=2(10 +8)=36\)$.
Therefore, each side of the square is $\(\frac{36}{4}=9\)$.
Now that we have the sides of the square, we can find the area by squaring the length of one side.
Area of square $\(=9^2=81\)$.
The quantities are equal; the answer is (C).
The perimeter of a rectangle is $\(2(l+w)=2(10 +8)=36\)$.
Therefore, each side of the square is $\(\frac{36}{4}=9\)$.
Now that we have the sides of the square, we can find the area by squaring the length of one side.
Area of square $\(=9^2=81\)$.
The quantities are equal; the answer is (C).
gmatclubot
Re: The area of a square region with a perimeter equal to the perimeter of [#permalink]
01 Nov 2025, 13:55
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