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Re: The area of an equilateral triangle with a side length of 4 [#permalink]
Olasunbo wrote:
An Equilateral triangle can be further broken into 30:60:90 triangle, then the hypotenuse will be 4, shortest side will be 2 while the medium side(height of the triangle) will be 2√3 (following the law of 30:60:90 triangle x:x√3:2x)
The the area will be 1/2*4*2√3= 4√3...


Hi, can you please explain how did you get 2\(\sqrt{3}\)as one of the sides of equilateral triangle? if x = 4 then why x\(\sqrt{3}\) is not equal to 4\(\sqrt{3}\)?
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Re: The area of an equilateral triangle with a side length of 4 [#permalink]
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Farina wrote:
Olasunbo wrote:
An Equilateral triangle can be further broken into 30:60:90 triangle, then the hypotenuse will be 4, shortest side will be 2 while the medium side(height of the triangle) will be 2√3 (following the law of 30:60:90 triangle x:x√3:2x)
The the area will be 1/2*4*2√3= 4√3...


Hi, can you please explain how did you get 2\(\sqrt{3}\)as one of the sides of equilateral triangle? if x = 4 then why x\(\sqrt{3}\) is not equal to 4\(\sqrt{3}\)?

Remember the triangle is broken into 2 equal part(30:60:90) hence the base is divided into 2 equal part

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