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Re: The “aspect ratio” of a computer monitor is the ratio of the
[#permalink]
05 Jul 2018, 01:44
Explanation
Rather than assigning separate variables to the width and height, define them both in terms of the same unknown multiplier, based on the ratio given:
Width = 16m
Height = 9m
Remember that the question asks for the width, so answer for 16m, not for m!
The perimeter of a rectangle is equal to 2(length + width), or in this case 2(width + height):
\(100 = 2 \times (16m + 9m)\)
\(100 = 50m\)
\(m = 2\)
\(16m = 32\)
An alternative method depends on the same underlying logic, but forgoes the algebra. Suppose the dimensions were 16 inches and 9 inches. This would yield a perimeter of 50 inches. Double the width and height to double the perimeter.
Hence option C is correct!