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The average (arithmetic mean) of 100, 101, and 103 The media
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16 Oct 2018, 09:56
16 Oct 2018, 09:56
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Question Stats:
84% (00:22) correct
16% (00:18) wrong based on 75 sessions
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Quantity A |
Quantity B |
The average (arithmetic mean) of 100, 101, and 103 |
The median of 100, 101, and 103 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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Re: The average (arithmetic mean) of 100, 101, and 103 The media
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18 Oct 2018, 09:00
18 Oct 2018, 09:00
1
Carcass wrote:
Quantity A |
Quantity B |
The average (arithmetic mean) of 100, 101, and 103 |
The median of 100, 101, and 103 |
The median of 100, 101, and 103 is 101
So, we have:
Quantity A: (100 + 101 + 103)/3
Quantity B: 101
We have a few options from here.
One approach is to multiply both quantities by 3 to get:
Quantity A: 100 + 101 + 103
Quantity B: 303
Evaluate Quantity A to get:
Quantity A: 304
Quantity B: 303
Answer: A
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Re: The average (arithmetic mean) of 100, 101, and 103 The media [#permalink]
18 Oct 2018, 09:00
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