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The average (arithmetic mean) of 3^2, 3^4, 3^6
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09 Jun 2026, 11:25
09 Jun 2026, 11:25
Expert Reply
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Question Stats:
88% (00:47) correct
11% (00:49) wrong based on 17 sessions
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Quantity A |
Quantity B |
The average (arithmetic mean) of \( 3^2, 3^4, 3^6\) |
\(3^4\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
- Part of the project: GRE Daily Quant Challenge - Topic-Wise 2025!!!
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GRE Prep Club Team Member
Joined: 20 Feb 2017
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Re: The average (arithmetic mean) of 3^2, 3^4, 3^6
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12 Jun 2026, 00:12
12 Jun 2026, 00:12
1
Expert Reply
Explanation
Quantity A = \(\frac{3^2 + 3^4 + 3^6}{3}\)
Quantity A = \(\frac{3(3^1 + 3^3 + 3^5)}{3}\)
Quantity A = \(3 + 27 + 243 = 273\)
Quantity B = \(3*3*3*3 = 81\)
Quantity A is greater
Answer: A
Quantity A = \(\frac{3^2 + 3^4 + 3^6}{3}\)
Quantity A = \(\frac{3(3^1 + 3^3 + 3^5)}{3}\)
Quantity A = \(3 + 27 + 243 = 273\)
Quantity B = \(3*3*3*3 = 81\)
Quantity A is greater
Answer: A
gmatclubot
Re: The average (arithmetic mean) of 3^2, 3^4, 3^6 [#permalink]
12 Jun 2026, 00:12
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