GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The average (arithmetic mean) of the 5 positive integers k, m, r, s, a
[#permalink]
22 Sep 2024, 23:48
22 Sep 2024, 23:48
Expert Reply
00:00
Question Stats:
90% (02:40) correct
10% (01:20) wrong based on 10 sessions
Hide Show timer Statistics
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, where, k < m < r < s < t. If t = 40, what is the greatest possible value of the median of these 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22
A. 16
B. 18
C. 19
D. 20
E. 22
- Part of the project: GRE Quant & Verbal ADVANCED Daily Challenge 2024 Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
- Also replying to the unanswered questions
The average (arithmetic mean) of the 5 positive integers k, m, r, s, a
[#permalink]
23 Sep 2024, 13:24
23 Sep 2024, 13:24
1
If the average of the 5 numbers is 16, their sum will be 80
t = 40 the largest.
Using the principle of max/min we will need to reduce k and m to the least possible, therefore
k = 1
m = 2
Since t = 40, that leaves us with 37 for the two remaining values, r and s. Since there are odd number of terms, r will have to be the median so s = 19 and r = 18
Answer B
t = 40 the largest.
Using the principle of max/min we will need to reduce k and m to the least possible, therefore
k = 1
m = 2
Since t = 40, that leaves us with 37 for the two remaining values, r and s. Since there are odd number of terms, r will have to be the median so s = 19 and r = 18
Answer B
Re: The average (arithmetic mean) of the 5 positive integers k, m, r, s, a
[#permalink]
06 Oct 2024, 15:57
06 Oct 2024, 15:57
adewale223 wrote:
If the average of the 5 numbers is 16, their sum will be 80
t = 40 the largest.
Using the principle of max/min we will need to reduce k and m to the least possible, therefore
k = 1
m = 2
Since t = 40, that leaves us with 37 for the two remaining values, r and s. Since there are odd number of terms, r will have to be the median so s = 19 and r = 18
Answer B
t = 40 the largest.
Using the principle of max/min we will need to reduce k and m to the least possible, therefore
k = 1
m = 2
Since t = 40, that leaves us with 37 for the two remaining values, r and s. Since there are odd number of terms, r will have to be the median so s = 19 and r = 18
Answer B
What is principle of max/min ??Can you please Elaborate??
