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The average (arithmetic mean) of the numbers above

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sandy
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The average (arithmetic mean) of the numbers above [#permalink] New post   22 Nov 2017, 18:49
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2, 3, 5, 7

Quantity A
Quantity B
The average (arithmetic mean) of the numbers above
The median of the numbers above


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

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Re: The average (arithmetic mean) of the numbers above [#permalink] New post   09 Dec 2017, 19:44
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Explanation

The mean is found by dividing the sum of the elements by the number of elements. In this case: 2 + 3 + 5 + 7 = 17, and 17 ÷ 4 = 4.25, the mean. The median is the middle number, or, if the list contains an even number of elements, the average of the middle two elements (when they are arranged
in increasing order). In this case, the average of 3 and 5 is 4.

Quantity A is greater than Quantity B.
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Re: The average (arithmetic mean) of the numbers above [#permalink] New post   05 Aug 2022, 23:52
Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of all the Values = Average * Total Number of Values
    ➡ In case of even number of numbers in the set: Median is the mean of the two middle numbers (after the numbers are arranged in the increasing / decreasing order)
    ➡ In case of odd number of numbers in the set: Median is the middle number (after the numbers are arranged in increasing/ decreasing order)

Quantity A

The average (arithmetic mean) of 2, 3, 5, 7

Average = \(\frac{Sum}{4}\) = \(\frac{2 + 3 + 5 + 7}{4}\) = \(\frac{17}{4}\) = 4.25

Quantity B

Median of 2, 3, 5, 7

Since, there are even number (4) of values so Median = Mean of middle two terms = \(\frac{3 + 5}{2}\) = \(\frac{8}{2}\) = 4

Clearly, Quantity A(4.25) > Quantity B(4)

So, Answer will be A.
Hope it helps!

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Re: The average (arithmetic mean) of the numbers above [#permalink]
05 Aug 2022, 23:52
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