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The average length of all the sides of a rectangle equals tw
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11 Apr 2019, 16:06
11 Apr 2019, 16:06
Expert Reply
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Question Stats:
70% (01:23) correct
30% (00:55) wrong based on 10 sessions
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The average length of all the sides of a rectangle equals twice the width of the rectangle. If the area of the rectangle is 18, what is its perimeter?
(A) \(6\sqrt{6}\)
(B) \(8\sqrt{6}\)
(C) 24
(D) 32
(E) 48
(A) \(6\sqrt{6}\)
(B) \(8\sqrt{6}\)
(C) 24
(D) 32
(E) 48
Re: The average length of all the sides of a rectangle equals tw
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15 Apr 2020, 11:27
15 Apr 2020, 11:27
Expert Reply
l*b = 18 -------- given
(2b+2l)/4 = 2b
6b = 2l
3b = l
3*18/l = l (using the given data)
l2l2 = 54
l = 3√6
therefore b = √6
perimeter = 2*(3√6+√6) = 8√6
Hence option B is correct
(2b+2l)/4 = 2b
6b = 2l
3b = l
3*18/l = l (using the given data)
l2l2 = 54
l = 3√6
therefore b = √6
perimeter = 2*(3√6+√6) = 8√6
Hence option B is correct
gmatclubot
Re: The average length of all the sides of a rectangle equals tw [#permalink]
15 Apr 2020, 11:27
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