GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
The average of five consecutive integers starting from m
[#permalink]
11 Apr 2019, 16:21
11 Apr 2019, 16:21
1
Expert Reply
00:00
Question Stats:
66% (00:50) correct
33% (00:27) wrong based on 159 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
The average of five consecutive integers starting from m |
The average of six consecutive integers starting from m |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
The average of five consecutive integers starting from m
[#permalink]
11 Apr 2019, 16:29
11 Apr 2019, 16:29
1
Carcass wrote:
Quantity A |
Quantity B |
The average of five consecutive integers starting from m |
The average of six consecutive integers starting from m |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
QUANTITY A: The average of five consecutive integers starting from m
So, the 5 numbers are: m, m+1, m+2, m+3 and m+4
Average = (m + m+1 + m+2 + m+3 + m+4)/5
= (5m + 10)/5
= m + 2
QUANTITY B: The average of six consecutive integers starting from m
So, the 6 numbers are: m, m+1, m+2, m+3, m+4 and m+5
Average = (m + m+1 + m+2 + m+3 + m+4 + m+6)/6
= (6m + 15)/6
= m + 2.5
We have:
QUANTITY A: m + 2
QUANTITY B: m + 2.5
Subtract m from both quantities to get:
QUANTITY A: 2
QUANTITY B: 2.5
Answer: B
RELATED VIDEO FROM OUR COURSE
Re: The average of five consecutive integers starting from m
[#permalink]
23 Sep 2019, 23:21
23 Sep 2019, 23:21
Can we consider negative integers?
