Triangles? Should I divide the square in two triangles? I really don't get how a triangle matters in a comparison between a circle and a square

Sorry for the mismatch. My pdf is so tight that I wrote the explanation of the previous question. Apologize.

Fixed both the OA and OE

can someone please explain it ... I didn't get above-mentioned solution

thanks in advance for your kindness

Let the radius of circle be \(r\) and side of square be \(a\)

Given \(2πr = \frac{7}{8}(4a)\)

i.e. \(\frac{2πr(8)}{7(4)} = a\)

\(a = \frac{4πr}{7}\)

Now,
Col. A: \(a^2\)
Col. B: \(πr^2\)

Put the value of \(a\) in Col. A;

Col. A: \((\frac{4πr}{7})^2\)

Col. B: \(πr^2\)

Col. A: \(\frac{16π^2r^2}{49}\)

Col. B: \(πr^2\)

Dividing both sides by \(πr^2\);

Col. A: \(\frac{16π}{49}\)

Col. B: \(1\)

Multiplying both sides by \(49\);

Col. A: \(16π\)
Col. B: \(49\)

Put \(π = 3.14\),

Col. A: \(50.24\)
Col. B: \(49\)

Hence, option A

Hi Carcass, can you rewrite the question for better clarity from \(\frac{7}{8}\) to simply 7/8.

Edit: Basically, there is something wrong with the formatting. Pls check the question and do the needful.

Maybe you have some issue to visualize the question.

I do not see any issue in 7/8 formatted in latex

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