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The equation of a line L is 3y-12x=12
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22 Jul 2025, 00:10
22 Jul 2025, 00:10
Expert Reply
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Question Stats:
73% (00:44) correct
26% (00:34) wrong based on 23 sessions
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The equation of a line L is \(3y-12x=12\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The x-intercept of line L |
The y-intercept of line L |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: The equation of a line L is 3y-12x=12
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29 Jul 2025, 12:33
29 Jul 2025, 12:33
Expert Reply
Given the line equation:
$$
\(3 y-12 x=12\)
$$
Let's find the x -intercept and y -intercept.
Step 1: Find the x -intercept
The $x$-intercept occurs when $y=0$.
Substitute $y=0$ into the equation:
$$
\(3(0)-12 x=12 \Longrightarrow-12 x=12 \Longrightarrow x=-1\)
$$
So, x -intercept $=-1$.
Step 2: Find the $y$-intercept
The $y$-intercept occurs when $x=0$.
Substitute $x=0$ into the equation:
$$
\(3 y-12(0)=12 \Longrightarrow 3 y=12 \Longrightarrow y=4\)
$$
So, y -intercept $=4$.
Compare Quantity A and Quantity B
- Quantity A $\(=x\)$-intercept $\(=-1\)$
- Quantity $\(\mathrm{B}=y\)$-intercept $\(=4\)$
Since $\(4>-1\)$,
Quantity $B$ is greater than Quantity $A$.
$$
\(3 y-12 x=12\)
$$
Let's find the x -intercept and y -intercept.
Step 1: Find the x -intercept
The $x$-intercept occurs when $y=0$.
Substitute $y=0$ into the equation:
$$
\(3(0)-12 x=12 \Longrightarrow-12 x=12 \Longrightarrow x=-1\)
$$
So, x -intercept $=-1$.
Step 2: Find the $y$-intercept
The $y$-intercept occurs when $x=0$.
Substitute $x=0$ into the equation:
$$
\(3 y-12(0)=12 \Longrightarrow 3 y=12 \Longrightarrow y=4\)
$$
So, y -intercept $=4$.
Compare Quantity A and Quantity B
- Quantity A $\(=x\)$-intercept $\(=-1\)$
- Quantity $\(\mathrm{B}=y\)$-intercept $\(=4\)$
Since $\(4>-1\)$,
Quantity $B$ is greater than Quantity $A$.
Re: The equation of a line L is 3y-12x=12
[#permalink]
29 Jul 2025, 12:33
29 Jul 2025, 12:33
Expert Reply
Given the line equation:
$$
\(3 y-12 x=12\)
$$
Let's find the x -intercept and y -intercept.
Step 1: Find the x -intercept
The $x$-intercept occurs when $y=0$.
Substitute $y=0$ into the equation:
$$
\(3(0)-12 x=12 \Longrightarrow-12 x=12 \Longrightarrow x=-1\)
$$
So, x -intercept $=-1$.
Step 2: Find the $y$-intercept
The $y$-intercept occurs when $x=0$.
Substitute $x=0$ into the equation:
$$
\(3 y-12(0)=12 \Longrightarrow 3 y=12 \Longrightarrow y=4\)
$$
So, y -intercept $=4$.
Compare Quantity A and Quantity B
- Quantity A $\(=x\)$-intercept $\(=-1\)$
- Quantity $\(\mathrm{B}=y\)$-intercept $\(=4\)$
Since $\(4>-1\)$,
Quantity $B$ is greater than Quantity $A$.
$$
\(3 y-12 x=12\)
$$
Let's find the x -intercept and y -intercept.
Step 1: Find the x -intercept
The $x$-intercept occurs when $y=0$.
Substitute $y=0$ into the equation:
$$
\(3(0)-12 x=12 \Longrightarrow-12 x=12 \Longrightarrow x=-1\)
$$
So, x -intercept $=-1$.
Step 2: Find the $y$-intercept
The $y$-intercept occurs when $x=0$.
Substitute $x=0$ into the equation:
$$
\(3 y-12(0)=12 \Longrightarrow 3 y=12 \Longrightarrow y=4\)
$$
So, y -intercept $=4$.
Compare Quantity A and Quantity B
- Quantity A $\(=x\)$-intercept $\(=-1\)$
- Quantity $\(\mathrm{B}=y\)$-intercept $\(=4\)$
Since $\(4>-1\)$,
Quantity $B$ is greater than Quantity $A$.
