For a parabola say $\(y=x^2\)$ if a point say $(a, b)$ lies

1. On the parabola, we get $\(b=a^2\)$
2. Inside the parabola, we get $\(\mathrm{b}<\mathrm{a}^2\)$
3. outside the parabola, we get $\(b>a^2\)$

The point $\((s, t)\)$ lies inside the parabola $\(y=2 x-x^2\)$ (As shown in the figure).
So, we must have $\(\mathrm{t}<2 \mathrm{~s}-\mathrm{s}^2\)$
Hence column B gets higher quantity when compared with column B, so the answer is (B).