$\frac{13!}{7!} = \frac{(13)(12)(11)(10)(9)(8)(7)(6)(5)(4)(3)(2)(1)}{(7)(6)(5)(4)(3)(2)(1)}=(13)(12)(11)(10)(9)(8)$

(13)(12)(11)(10)(9)(8) is divisible by 3, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(10)(3)(3)(8). Eliminate A
(13)(12)(11)(10)(9)(8) is divisible by 5, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(5)(2)(9)(8). Eliminate B
(13)(12)(11)(10)(9)(8) is divisible by 6, because (13)(12)(11)(10)(9)(8) = (13)(7)(2)(11)(10)(9)(8). Eliminate C
(13)(12)(11)(10)(9)(8) is divisible by 6, because (13)(12)(11)(10)(9)(8) = (13)(12)(11)(10)(9)(8). Eliminate E

Answer: D

Cheers,
Brent