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Re: The figure above is made up of 4 squares. If a straight line [#permalink]
Carcass wrote:
Attachment:
#GRE practicequestion The figure above is made up of 4 squares.jpg


This becomes a triangle which has the angles in the ratio of \(45:45:90\) or \(x:x:x\sqrt{2}\)

We do know this because the segment AB is \(8\sqrt{2}\)

which means that the other sides are 8

One side of a square is 4.

We want to know the perimeter of the shaded region which has 10 sides

\(4 \times 10 = 40\)

C is the answer


Aren't we supposed to be told that all the squares are equal? By assuming that they are equal, we might be missing a case when they aren't.
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Re: The figure above is made up of 4 squares. If a straight line [#permalink]
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As square has all the sides equal.

Otherwise must be specified. In this case, we fairly might assume they are equal.

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Re: The figure above is made up of 4 squares. If a straight line [#permalink]
Carcass wrote:
As square has all the sides equal.

Otherwise must be specified. In this case, we fairly might assume they are equal.

Regards


The problem says "The figure above is made up of 4 squares." . We know that each of those four figures is a square, but we are not told that they are all equal.
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Re: The figure above is made up of 4 squares. If a straight line [#permalink]
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Each square is equal to another.

See also my explanation above https://gre.myprepclub.com/forum/the-figur ... tml#p35374

You could infer from it
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Re: The figure above is made up of 4 squares. If a straight line [#permalink]
Carcass wrote:
Attachment:
#GRE practicequestion The figure above is made up of 4 squares.jpg


The figure above is made up of 4 squares. If a straight line segment were to be drawn from A to B, it would have a length of \(8 \sqrt{2}\) units. What is the perimeter of the entire figure in units?

A. 20

B. 32

C. 40

D. 64

E. 80


across one square the distance would be \(4\sqrt{2}\)

\(4\sqrt{2} = \sqrt{2a^2}\)
16*2 = 32 = 2a^2
16 = a^2
a = 4

Then count edges. 10

4*10 = 40

Perhaps a faster way of doing the math would be putting 4 under the radical to get \sqrt{32} and recognizing that 16*2 so the length must be 4 for each side.
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