Carcass wrote:
The greatest possible distance between any two points on the surface of a cube is \(3 \sqrt{6}\). What is the total surface area of the cube?
36
\(27 \sqrt{3}\)
72
\(54 \sqrt{2}\)
108
Diagonal of a cube is the greatest distance between any 2 points on a cube
Diagonal of cube with edge length \(a\) is \(a\sqrt{3}\)
\(a\sqrt{3} = 3\sqrt{6}\)
\(a = \frac{3\sqrt{6}}{\sqrt{3}} = \frac{3(\sqrt{2})(\sqrt{3})}{\sqrt{3}} = 3\sqrt{2}\)
TSA = \(6a^2 = 6(3\sqrt{2})^2 = (6)(18) = 108\)
Hence, option E
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