GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The large rectangular solid shown here is formed by binding together n
[#permalink]
03 Feb 2023, 11:46
03 Feb 2023, 11:46
Expert Reply
00:00
Question Stats:
78% (02:16) correct
21% (01:25) wrong based on 23 sessions
Hide Show timer Statistics
Attachment:
GRE geometry (9).jpg [ 9.12 KiB | Viewed 1081 times ]
The large rectangular solid shown here is formed by binding together nine identical rectangular rods, as shown.
Quantity A |
Quantity B |
Four times the surface area of just one of the identical rectangular rods |
The surface area of the large rectangular solid above |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Re: The large rectangular solid shown here is formed by binding together n
[#permalink]
20 Feb 2023, 08:04
20 Feb 2023, 08:04
Expert Reply
OE
A rectangular solid has three pairs of opposing equal faces, each pair representing two of the dimensions of the solid (length × width; length × height; height × width). The total surface area of a rectangular solid is the sum of the surface areas of those three pairs of opposing sides. According to the diagram, the dimensions of each rod must be 1 × 1 × 6. So the surface area of one such rod is: 2(1 × 1) + 2(1 × 6) + 2(1 × 6) = 26 or 2[(1 × 1) + (1 × 6) + (1 × 6)] = 26 That is, one rod has a total surface area of 26, and four times this surface area is 4 × 26 = 104.
The large rectangular solid has a total surface area of: 2(3 × 3) + 2(3 × 6) + 2(3 × 6), or 90.
A > B
A rectangular solid has three pairs of opposing equal faces, each pair representing two of the dimensions of the solid (length × width; length × height; height × width). The total surface area of a rectangular solid is the sum of the surface areas of those three pairs of opposing sides. According to the diagram, the dimensions of each rod must be 1 × 1 × 6. So the surface area of one such rod is: 2(1 × 1) + 2(1 × 6) + 2(1 × 6) = 26 or 2[(1 × 1) + (1 × 6) + (1 × 6)] = 26 That is, one rod has a total surface area of 26, and four times this surface area is 4 × 26 = 104.
The large rectangular solid has a total surface area of: 2(3 × 3) + 2(3 × 6) + 2(3 × 6), or 90.
A > B
gmatclubot
Re: The large rectangular solid shown here is formed by binding together n [#permalink]
20 Feb 2023, 08:04
Moderators:
