GeminiHeat wrote:
The length of a certain rectangle is a multiple of 18, and the width of the rectangle is a multiple of 12. Which of the following CANNOT be the perimeter of the rectangle?
(A) 60
(B) 72
(C) 84
(D) 96
(E) 108
If length is a multiple of 18, then let L = 18x
If width is a multiple of 12, then let W = 12y
Perimeter = 2 (18x + 12y)
= 12 (3x + 2y)
Let us check the option choices;
A. 60 = 12 (3x + 2y)
(3x + 2y) = 5
3(1) + 2(1) = 5
B. 72 = 12 (3x + 2y)
(3x + 2y) = 6
No combination possibleC. 84 = 12 (3x + 2y)
(3x + 2y) = 7
3(1) + 2(2) = 7
D. 96 = 12 (3x + 2y)
(3x + 2y) = 8
3(2) + 2(1) = 8
E. 108 = 12 (3x + 2y)
(3x + 2y) = 9
3(1) + 2(3) = 9
Hence, option B