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The only items on a shelf are 8 green bins and 4 orange bins
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29 Sep 2020, 07:27
29 Sep 2020, 07:27
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Question Stats:
71% (01:20) correct
28% (01:45) wrong based on 45 sessions
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The only items on a shelf are 8 green bins and 4 orange bins. If 3 bins are to be selected from the shelf, one after the other, at random and without replacement, what is the probability that at least one green bin is selected?
Give your answer as a fraction.
Give your answer as a fraction.
Show: :: OA
\(\frac{54}{55}\)
Re: The only items on a shelf are 8 green bins and 4 orange bins
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01 Oct 2020, 02:17
01 Oct 2020, 02:17
3
Probability of at least one green beans is 1- probability of no green beans
Which is 4/12*3/11*2/10 = 1/55
Probability of at least one green beans is 1-1/55 = 54/55
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Which is 4/12*3/11*2/10 = 1/55
Probability of at least one green beans is 1-1/55 = 54/55
Posted from my mobile device
Re: The only items on a shelf are 8 green bins and 4 orange bins
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06 Feb 2023, 04:24
06 Feb 2023, 04:24
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
