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The operation @ is defined by the equation a@b = (a 1)(b
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30 Jul 2018, 10:27
30 Jul 2018, 10:27
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Question Stats:
62% (01:15) correct
37% (01:11) wrong based on 83 sessions
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The operation \(@\) is defined by the equation \(a@b = (a – 1)(b – 2)\).
\( x@5 = 3@x\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\( x@5 = 3@x\)
Quantity A |
Quantity B |
x |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: The operation @ is defined by the equation a@b = (a 1)(b
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01 Aug 2018, 09:12
01 Aug 2018, 09:12
1
x@5 = (x-1)(3)
= 3x - 3
3@x = 2(x-2)
= 2x - 4
From question,
3x - 3 = 2x - 4
or, x= -1
B>A
Posted from my mobile device
= 3x - 3
3@x = 2(x-2)
= 2x - 4
From question,
3x - 3 = 2x - 4
or, x= -1
B>A
Posted from my mobile device
Re: The operation @ is defined by the equation a@b = (a 1)(b
[#permalink]
12 Aug 2018, 05:36
12 Aug 2018, 05:36
Expert Reply
Explanation
This problem defines a function for the made-up symbol @. Use the definition of the new symbol to rewrite the equation x@5 = 3@x without the @ operator:
For x@5, a = x and b = 5: x@5 = (x – 1)(5 – 2) = 3x – 3.
For 3@x, a = 3 and b = x: 3@x = (3 – 1)(x – 2) = 2x – 4.
Equating these two expressions gives you:
\(3x - 3 = 2x - 4\)
\(x = -1\)
Quantity B is greater.
This problem defines a function for the made-up symbol @. Use the definition of the new symbol to rewrite the equation x@5 = 3@x without the @ operator:
For x@5, a = x and b = 5: x@5 = (x – 1)(5 – 2) = 3x – 3.
For 3@x, a = 3 and b = x: 3@x = (3 – 1)(x – 2) = 2x – 4.
Equating these two expressions gives you:
\(3x - 3 = 2x - 4\)
\(x = -1\)
Quantity B is greater.
