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The perimeter of a square is 48 inches. The length, in inche
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13 Sep 2019, 04:51
13 Sep 2019, 04:51
Expert Reply
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Question Stats:
95% (00:28) correct
4% (00:37) wrong based on 21 sessions
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The perimeter of a square is 48 inches. The length, in inches, of its diagonal is
A. \(6 \sqrt{2}\)
B. \(8 \sqrt{2}\)
C. \(12 \sqrt{2}\)
D. \(24 \sqrt{2}\)
E. \(48 \sqrt{2}\)
Kudos for the right answer and explanation
A. \(6 \sqrt{2}\)
B. \(8 \sqrt{2}\)
C. \(12 \sqrt{2}\)
D. \(24 \sqrt{2}\)
E. \(48 \sqrt{2}\)
Kudos for the right answer and explanation
Re: The perimeter of a square is 48 inches. The length, in inche
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20 Apr 2020, 15:48
20 Apr 2020, 15:48
Expert Reply
perimeter = 48
length of a side = 48 / 4 = 12
Area = \(12^2\) = 144.
we know ,
\(1/2d^2\)= area
\(1/2d^2 = 144\)
\(d^2\)= 2*144
d =\(\sqrt{2*144}\)
\(d = 12\sqrt{2}\)
Option C.
length of a side = 48 / 4 = 12
Area = \(12^2\) = 144.
we know ,
\(1/2d^2\)= area
\(1/2d^2 = 144\)
\(d^2\)= 2*144
d =\(\sqrt{2*144}\)
\(d = 12\sqrt{2}\)
Option C.
gmatclubot
Re: The perimeter of a square is 48 inches. The length, in inche [#permalink]
20 Apr 2020, 15:48
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