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The perimeter of a square is 48 inches. The length, in inche
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18 Mar 2020, 10:08
18 Mar 2020, 10:08
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The perimeter of a square is 48 inches. The length, in inches, of its diagonal is
A. \(6 \sqrt{2 }\)
B. \(8 \sqrt{2}\)
C. \(12 \sqrt{2}\)
D. \(24 \sqrt{2}\)
E. \(48 \sqrt{2}\)
Kudos for the right answer and explanation
A. \(6 \sqrt{2 }\)
B. \(8 \sqrt{2}\)
C. \(12 \sqrt{2}\)
D. \(24 \sqrt{2}\)
E. \(48 \sqrt{2}\)
Kudos for the right answer and explanation
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Re: The perimeter of a square is 48 inches. The length, in inche
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07 Jun 2020, 03:29
07 Jun 2020, 03:29
Perimeter of a square with a is 4*a = 48 inches (given)
=> 4a = 48 => a= 48/4 = 12
Diagonal of a square with side a = a\(\sqrt{2}\)
=> Length of diagonal = a\(\sqrt{2}\)= 12\(\sqrt{2}\)
So, answer will be C
Hope it helps!
=> 4a = 48 => a= 48/4 = 12
Diagonal of a square with side a = a\(\sqrt{2}\)
=> Length of diagonal = a\(\sqrt{2}\)= 12\(\sqrt{2}\)
So, answer will be C
Hope it helps!
gmatclubot
Re: The perimeter of a square is 48 inches. The length, in inche [#permalink]
07 Jun 2020, 03:29
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