Last visit was: 17 May 2024, 16:43 It is currently 17 May 2024, 16:43


GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

for You

we will pick new questions that match your level based on your Timer History

Your Progress

every week, we’ll send you an estimated GRE score based on your performance


we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.


Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 28756
Own Kudos [?]: 33335 [1]
Given Kudos: 25245
Send PM
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Own Kudos [?]: 356 [0]
Given Kudos: 64
GRE 1: Q160 V152
Send PM
Joined: 23 May 2021
Posts: 146
Own Kudos [?]: 45 [0]
Given Kudos: 23
Send PM
Retired Moderator
Joined: 02 Dec 2020
Posts: 1833
Own Kudos [?]: 2125 [1]
Given Kudos: 140
GRE 1: Q168 V157

GRE 2: Q167 V161
Send PM
Re: The positive integer q is divisible by 15. If the product of q and the [#permalink]
\(q\) is divisible by \(3\) & \(5\), hence the least +ve value of \(q\) can be \(15\)

\(qx\) is divisible by \(20\).
Factors of \(20: 2 * 2 * 5\)

\(5\) is already there with \(q\) so we will need \(4\), which can be the least value of \(x\)

So we can say that \(x^2q\) will have at least \(4\) & \(15\)

Hence, \(60\) must be a factor of \(x^2q\)

Answer B

aishumurali wrote:
Can someone pls explain this sum?
Prep Club for GRE Bot
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne