Let the price at Store B be $x$.
Store A's price is $\(\frac{1}{3}\)$ more than Store B's price, so:

$$
\(\text { Price at Store } \mathrm{A}=x+\frac{1}{3} x=\frac{4}{3} x\)
$$


The difference in prices is $\backslash \$ 0.35$ :

$$
\(\frac{4}{3} x-x=0.35\)
$$


Simplify:

$$
\(\frac{4}{3} x-\frac{3}{3} x=\frac{1}{3} x=0.35\)
$$


Multiply both sides by 3 :

$$
\(x=0.35 \times 3=1.05\)
$$


Price at Store A is:

$$
\(\frac{4}{3} \times 1.05=\frac{4 \times 1.05}{3}=\frac{4.2}{3}=1.4
$$\)


Final answer:
C. $\(\$ 1.40\)$