Explanation

The probability of independent events A and B occurring is equal to the product of the probability of event A and the probability of event B.

In this case, the probability of the coin turning up heads is $\frac{1}{2}$ and the probability of rolling a 6 is $\frac{1}{6}$. Therefore, the probability of heads and a 6 is equal to $\frac{1}{2}\times\frac{1}{6}=\frac{1}{12}$.

Alternatively, list all the possible outcomes: H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6.

There are 12 total outcomes and only 1 with heads and a 6. Therefore, the desired outcome divided by the total number of outcomes is equal to $\frac{1}{12}$.