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The ratio of two adult brothers' ages is 5 to 8.
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05 Nov 2017, 01:04
05 Nov 2017, 01:04
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57% (01:27) correct
42% (01:09) wrong based on 133 sessions
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The ratio of two adult brothers' ages is 5 to 8.
Quantity A |
Quantity B |
The ratio of the brothers' ages 8 years ago. |
The ratio of the brothers' ages in 6 years. |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: The ratio of two adult brothers' ages is 5 to 8.
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05 Nov 2017, 02:50
05 Nov 2017, 02:50
1
Whatever ages we decide to use, with the only restriction of being both greater than 8 (otherwise B would be negative and age cannot be negative), we get quantity B is greater.
For example, if the ages were 10 and 16 (2*5 and 2*8), quantity A would be 2/8 and quantity B 4/10, thus B is greater.
Answer B
For example, if the ages were 10 and 16 (2*5 and 2*8), quantity A would be 2/8 and quantity B 4/10, thus B is greater.
Answer B
Re: The ratio of two adult brothers' ages is 5 to 8.
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24 Feb 2018, 09:56
24 Feb 2018, 09:56
1
we can compare a/b and (a-1)/(b-1) to see the logic behind this type of question.
assume a and b >1:
a/b ? a-1/b-1 =a(b-1)?b(a-1)=ab-a?ba-b=-a?-b
When a is smaller than b: -a>-b the one close to original number is larger.
When a is smaller than b: -a<-b the one further from the original number is larger.
assume a and b >1:
a/b ? a-1/b-1 =a(b-1)?b(a-1)=ab-a?ba-b=-a?-b
When a is smaller than b: -a>-b the one close to original number is larger.
When a is smaller than b: -a<-b the one further from the original number is larger.
