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Re: The remainder when 120 is divided by single-digit integer m [#permalink]
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The key clue here is that we're dealing with a single-digit number and that the remainder is positive. Discovering this requires close evaluation of the question.

This heavily narrows down our options. 1, 2, 3, 4, 5, 6, and 8 will all yield a remainder of 0 because they are all factors of 120. This leaves us with 7 and 9.

Subtracting the lesser from the greater, we get 2. When we divide 120 by 2, our remainder is 0.

Hence, our answer is 0.
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Re: The remainder when 120 is divided by single-digit integer m [#permalink]
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Neat question.
Notice the restrictions - m and n must be digits.
Therefore, m and n can take values from 1 to 9, inclusive.
0 is excluded, as we are dividing.
120 can be divided by 1,2,3,4,5, 6 and 8.
As we know that the remainder is positive, m and n cannot be any of those values.
as m>n, m must be 9 and n must be 7.
Therefore, m-n=2, which leaves no remainder when dividing by 120. 0 is the correct answer.
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