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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
The sequence S is defined as follows for all n ≥ 1: The sum of the
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09 Jul 2021, 08:01
09 Jul 2021, 08:01
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The sequence S is defined as follows for all n ≥ 1:
\(S_n=(-1)^n*\frac{1}{n(n+1)}\)
The sum of the first 10 terms of S is:
(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1
\(S_n=(-1)^n*\frac{1}{n(n+1)}\)
The sum of the first 10 terms of S is:
(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
Re: The sequence S is defined as follows for all n ≥ 1: The sum of the
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17 Jul 2021, 23:23
17 Jul 2021, 23:23
Expert Reply
+1 Kudos to posts containing answer with explanation
Re: The sequence S is defined as follows for all n ≥ 1: The sum of the
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07 Sep 2021, 06:56
07 Sep 2021, 06:56
GeminiHeat wrote:
The sequence S is defined as follows for all n ≥ 1:
\(S_n=(-1)^n*\frac{1}{n(n+1)}\)
The sum of the first 10 terms of S is:
(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1
\(S_n=(-1)^n*\frac{1}{n(n+1)}\)
The sum of the first 10 terms of S is:
(A) Between –1 and –1/2
(B) Between –1/2 and 0
(C) Between 0 and 1/2
(D) Between 1/2 and 1
(E) Greater than 1
Could someone please explain their approach
