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The set S consists of 4 consecutive integers. The second term in the s
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07 Jan 2023, 01:47
07 Jan 2023, 01:47
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Question Stats:
55% (01:03) correct
44% (01:23) wrong based on 18 sessions
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The set S consists of 4 consecutive integers. The second term in the set is n.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The average value of the integers in set S |
\(n+\frac{1}{2}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: The set S consists of 4 consecutive integers. The second term in the s
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31 Jan 2023, 10:51
31 Jan 2023, 10:51
Expert Reply
OE
Given the fact that the integers in set S are consecutive and the value of the second term is n, the remaining terms can be expressed as n − 1, n + 1, and n + 2, with n − 1 the first term in the sequence.
The average of a set of numbers can be expressed as (Sum) ÷ (Number of Terms), which for this problem equals:
\(\frac{(n-1)+n+(n+1)+(n+2)}{4}=n+\frac{1}{2}\)
C is the answer
Given the fact that the integers in set S are consecutive and the value of the second term is n, the remaining terms can be expressed as n − 1, n + 1, and n + 2, with n − 1 the first term in the sequence.
The average of a set of numbers can be expressed as (Sum) ÷ (Number of Terms), which for this problem equals:
\(\frac{(n-1)+n+(n+1)+(n+2)}{4}=n+\frac{1}{2}\)
C is the answer
gmatclubot
Re: The set S consists of 4 consecutive integers. The second term in the s [#permalink]
31 Jan 2023, 10:51
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