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The six digit number 679,3K0 is divisible by 3, 4, 5, and 9 if K is su
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13 Dec 2021, 23:34
13 Dec 2021, 23:34
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Question Stats:
70% (00:50) correct
30% (00:32) wrong based on 10 sessions
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The six digit number 679,3K0 is divisible by 3, 4, 5, and 9 if K is substituted by which of the following digits?
(A) 1
(B) 2
(C) 4
(D) 6
(E) 8
(A) 1
(B) 2
(C) 4
(D) 6
(E) 8
Re: The six digit number 679,3K0 is divisible by 3, 4, 5, and 9 if K is su
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14 Dec 2021, 08:41
14 Dec 2021, 08:41
1
\(679,3K0\) is divisible by \(3, 4, 5,\) and \(9\)
The no is divisible by 9 so the sum of the digits \(= 6 + 7 + 9 + 3 + K + 0 = 25 + K\)
\(25 + K\) must be divisible by \(9\) and the only value possible for \(K\) is \(2\)
Answer B
The no is divisible by 9 so the sum of the digits \(= 6 + 7 + 9 + 3 + K + 0 = 25 + K\)
\(25 + K\) must be divisible by \(9\) and the only value possible for \(K\) is \(2\)
Answer B
gmatclubot
Re: The six digit number 679,3K0 is divisible by 3, 4, 5, and 9 if K is su [#permalink]
14 Dec 2021, 08:41
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