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The square of the sum of two numbers is 289. The product of the tw
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12 Mar 2024, 04:27
12 Mar 2024, 04:27
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The square of the sum of two numbers is 289. The product of the two numbers is 66. What is the sum of the squares of the two numbers?
A. 155
B. 157
C. 159
D. 160
E. 162
A. 155
B. 157
C. 159
D. 160
E. 162
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Free Materials for the GRE General Exam - Where to get it!!
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The square of the sum of two numbers is 289. The product of the tw
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11 May 2024, 12:33
11 May 2024, 12:33
1
Let c and d be the two numbers. Since the square of the sum of c and d is 289, \((c+d)^2 = 289\).
Expand:
\((c+d)^2 = 289\)
\(c^2+2cd+d^2 = 289\)
Substitute cd=66 into it and simplify:
\(c^2 + 2(66) + d^2 = 289\)
\(c^2 + d^2 = 157\)
Now we're left with the sum of the squares of c and d.
Expand:
\((c+d)^2 = 289\)
\(c^2+2cd+d^2 = 289\)
Substitute cd=66 into it and simplify:
\(c^2 + 2(66) + d^2 = 289\)
\(c^2 + d^2 = 157\)
Now we're left with the sum of the squares of c and d.
gmatclubot
The square of the sum of two numbers is 289. The product of the tw [#permalink]
11 May 2024, 12:33
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