Re: The straight line having a slope of passes through the point (3, 5).
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22 Dec 2024, 13:08
The equation of line having slope $\(\frac{5}{3}\)$ is $\(y=\frac{5}{3} x+c\)$, where c is the y -intercept (The equation of a line having slope ' $\(m\)$ ' and $\(y\)$-intercept ' $\(c\)$ ' is $\(y=m x+c\)$ ).
As the line above passes through $\((3,5)\)$, we get $\(5=\frac{5}{3} \times 3+c \Rightarrow c=5-5=0^{-}\)$
So, the equation of line is $\(y=\frac{5}{3} x+0\)$ i.e. $\(3 y-5 x=0\)$
Now, checking from the options only $\((0,0)\)$ satisfy the equation, so pass through the straight line. Hence the answer is (B).