Quantity A	Quantity B
The sum of all the even integers from 18 to 36 inclusive	The sum of all the even integers from 22 to 38 inclusive

A)Quantity A is greater.
B)Quantity B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Hello,

Could you please check the forum before posting, this is duplication of the question. Moreover plz check the questions already posted under Princeton Review. U will find most of them.

For your reference this question is answered here:

https://gre.myprepclub.com/forum/the-sum-o ... 12325.html

Thank you for your reply.
The posted answer is exactly the same as the book explanation, and i still couldn't get it.
Maybe someone has another explanation.

So we have two quantitites..
1) A=Sum of all even numbers from 18 to 36 = 18+20+22+24+26+...34+36.
2) B=Sum of all even numbers from 22 to 38 = 22+24+26+...34+36+38.
Let 22+24+...36 be a, so A=18+20+a=38+a and B=a+38..
Thus A=B

another way..
1) A=Sum of all even numbers from 18 to 36 = 18+20+22+24+26+...34+36
Sum of consecutive numbers, or consecutive even integers is average * number of terms
Average = \(\frac{first+last}{2}=\frac{18+36}{2}=27\)
Number of terms = \(\frac{36-18}{2}+1=9+1=10\)
Sum = 27*10=270

2) B=Sum of all even numbers from 22 to 38 = 22+24+26+...34+36+38.
Average = \(\frac{first+last}{2}=\frac{22+38}{2}=30\)
Number of terms = \(\frac{38-22}{2}+1=8+1=9\)
Sum = 30*9=270
so A=B

C

Even if the u need an explanation to any post, just post a reply under the same post, u need not create a separate Question as it duplicates and the GRE moderator need to spend time in rectifying this.

I hope u do understand, and plz Next time first search in the forum, if u find a post reply there else create a new post.

For ur reference:

https://gre.myprepclub.com/forum/the-sum-o ... 10659.html

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