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The total weight of m peanuts at a weight of n + 3 mg eac
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03 Jun 2017, 02:12
03 Jun 2017, 02:12
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Question Stats:
88% (00:52) correct
11% (00:44) wrong based on 118 sessions
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Quantity A |
Quantity B |
The total weight of m peanuts at a weight of n + 3 mg each |
The total weight of n almonds at a weight of m + 3 mg each |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: The total weight of m peanuts at a weight of n + 3 mg eac
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20 Jun 2017, 09:10
20 Jun 2017, 09:10
1
Carcass wrote:
Quantity A |
Quantity B |
The total weight of m peanuts at a weight of n + 3 mg each |
The total weight of n almonds at a weight of m + 3 mg each |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
The total weight of m peanuts at a weight of (n + 3) milligrams each
Total weight = (m)(n + 3)
The total weight of n almonds at a weight of (m + 3) milligrams each
Total weight = (n)(m + 3)
So, we have:
Quantity A: (m)(n + 3)
Quantity B: (n)(m + 3)
Expand both quantities:
Quantity A: mn + 3m
Quantity B: nm + 3n
Subtract mn (aka nm) from both quantities:
Quantity A: 3m
Quantity B: 3n
Divide both quantities by 3 to get:
Quantity A: m
Quantity B: n
Since we are not given any information about the value of m and n, the correct answer must be D
Cheers,
Brent
Re: The total weight of m peanuts at a weight of n + 3 mg eac
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10 Feb 2019, 08:56
10 Feb 2019, 08:56
1
A= m*(n+3) = mn+3m
B= n*(m+3) = mn+3m
Since we don't know the value of m and n we can't determine which is greater.
Answer is D
B= n*(m+3) = mn+3m
Since we don't know the value of m and n we can't determine which is greater.
Answer is D
