GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The volume of a right circular cylinder with height equal to 15x and d
[#permalink]
11 Jun 2021, 06:22
11 Jun 2021, 06:22
1
1
Expert Reply
00:00
Question Stats:
74% (01:23) correct
25% (01:28) wrong based on 35 sessions
Hide Show timer Statistics
Attachment:
GRE The volume of a right circular.png [ 16.97 KiB | Viewed 2256 times ]
Quantity A |
Quantity B |
The volume of a right circular cylinder with height equal to 15x and diameter equal to 1y |
The volume of a right circular cylinder with height equal to 1x and diameter equal to 4y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: The volume of a right circular cylinder with height equal to 15x and d
[#permalink]
11 Jun 2021, 07:42
11 Jun 2021, 07:42
1
Volume of a cylinder = \(πr^2h\) , r - radius & h - height
Qt A
\(r = \frac{y}{2}\) & \(h = 15x\)
\(V = π * \frac{y}{2}^2 * 15x\) = \(\frac{15πxy^2}{4}\) = \(3.75πxy^2\)
Qt B
\(r = 2y\) & \(h = 1x\)
\(V = π * (2y)^2 * 1x\) = \(4πxy^2\)
Qt B > Qt A
Answer B
Qt A
\(r = \frac{y}{2}\) & \(h = 15x\)
\(V = π * \frac{y}{2}^2 * 15x\) = \(\frac{15πxy^2}{4}\) = \(3.75πxy^2\)
Qt B
\(r = 2y\) & \(h = 1x\)
\(V = π * (2y)^2 * 1x\) = \(4πxy^2\)
Qt B > Qt A
Answer B
Re: The volume of a right circular cylinder with height equal to 15x and d
[#permalink]
28 Aug 2022, 11:49
28 Aug 2022, 11:49
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
