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The volume of a sphere with radius r is (4/3)*pi*r^3. A solid sphere
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25 Nov 2021, 04:00
Expert Reply
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Question Stats:
50% (01:43) correct
50% (05:26) wrong based on 4 sessions
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The volume of a sphere with radius r is \(\frac {4}{3} \pi r^3\). A solid sphere of radius r that is made of a certain material weighs 40 pounds. The figure above shows half of a spherical shell made of the same material. What is the weight, in pounds, of the entire spherical shell if the outer radius is 5r and the inner radius is 2r?
Re: The volume of a sphere with radius r is (4/3)*pi*r^3. A solid sphere
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26 Nov 2021, 06:09
Expert Reply
Weight of the sphere with radius r is =40 Now the radius of the outer shell =5r if we consider it as sphere then its weight would be 125 times 40=5000 Now the sphere with inner radius 2r will have 8 times 40 as weight =320 Subtract the weight ans we get the weight of the shell =5000-320=4680
gmatclubot
Re: The volume of a sphere with radius r is (4/3)*pi*r^3. A solid sphere [#permalink]