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The width of a rectangle w is twice the length of the rectan
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19 Aug 2018, 03:35
19 Aug 2018, 03:35
Expert Reply
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Question Stats:
76% (00:45) correct
23% (00:40) wrong based on 43 sessions
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The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?
(A) \(w\)
(B) \(2w^2\)
(C) \(3w^2\)
(D) \(\frac{w^2}{2}\)
(E) \(\frac{w^2}{4}\)
(A) \(w\)
(B) \(2w^2\)
(C) \(3w^2\)
(D) \(\frac{w^2}{2}\)
(E) \(\frac{w^2}{4}\)
Re: The width of a rectangle w is twice the length of the rectan
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07 Jan 2019, 15:36
07 Jan 2019, 15:36
Length = w
width = w/2
Area = w * w/2
=w^2/4
Answer. D
width = w/2
Area = w * w/2
=w^2/4
Answer. D
Re: The width of a rectangle w is twice the length of the rectan
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14 Sep 2022, 02:18
14 Sep 2022, 02:18
1
AE wrote:
Length = w
width = w/2
Area = w * w/2
=w^2/4
Answer. D
width = w/2
Area = w * w/2
=w^2/4
Answer. D
I think there is a type here and the Area is
Area = w * (w/2)
= (w^2)/2
The 2 doesn't become 4
Which is option D.
