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There are 14 girls and eight boys in a classroom
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29 Apr 2022, 02:00
29 Apr 2022, 02:00
1
Expert Reply
00:00
Question Stats:
66% (01:08) correct
33% (00:55) wrong based on 45 sessions
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There are 14 girls and eight boys in a classroom
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
the number of ways to choose two of the girls |
the number of ways the to choose three of the boys |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: There are 14 girls and eight boys in a classroom
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30 Apr 2022, 11:43
30 Apr 2022, 11:43
1
The number of ways to choose 2 of the girls from 16 girls = 16C2
The number of ways to choose 3 of the boys from 8 girls = 8C3
Option A>B, hence correct ans
The number of ways to choose 3 of the boys from 8 girls = 8C3
Option A>B, hence correct ans
There are 14 girls and eight boys in a classroom
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28 Dec 2024, 21:26
28 Dec 2024, 21:26
I think the answer here is option B
Let's see
Quantity A = 14C2 = 14!/(2! x 12!)
= 14x13x12!/(2 x 12!)
= 14x13/2
= 7x13
= 51
Quantity B = 8C3 = 8!(3! x 5!)
= 8x7x6x5!/(3x2 x 5!)
= 8x7x6/6
= 8x7
= 56
Hence Option B, can you please correct the official answer. Carcass
Let's see
Quantity A = 14C2 = 14!/(2! x 12!)
= 14x13x12!/(2 x 12!)
= 14x13/2
= 7x13
= 51
Quantity B = 8C3 = 8!(3! x 5!)
= 8x7x6x5!/(3x2 x 5!)
= 8x7x6/6
= 8x7
= 56
Hence Option B, can you please correct the official answer. Carcass
