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There are 35 females in a club having an average age of f, and 45 ma
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30 Sep 2024, 00:42
30 Sep 2024, 00:42
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Question Stats:
80% (02:17) correct
20% (02:01) wrong based on 5 sessions
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There are 35 females in a club having an average age of ‘f’, and 45 males in the same club having an average age of ‘m’. ‘f’ is greater than ‘m’
Quantity A |
Quantity B |
Average age of all the 80 members of the club |
\(\frac{f+m}{2} \) |
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Re: There are 35 females in a club having an average age of f, and 45 ma
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09 Oct 2024, 22:52
09 Oct 2024, 22:52
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Averages are always tricky, find the sum of each ie sum/35=f hence sum age of females= 35*f
Quantity A would be: (35f+45m )/ 80
Plug in some values taking f>m in consideration (I just take simple values like 2 and 1)
Answer is B
boom!
Quantity A would be: (35f+45m )/ 80
Plug in some values taking f>m in consideration (I just take simple values like 2 and 1)
Answer is B
boom!
gmatclubot
Re: There are 35 females in a club having an average age of f, and 45 ma [#permalink]
09 Oct 2024, 22:52
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