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Three times the number of units in the perimeter of the figu

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Three times the number of units in the perimeter of the figu [#permalink] New post   28 Jul 2020, 10:19
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GRE Three times the number of units in the perimeter of the figure.jpg
GRE Three times the number of units in the perimeter of the figure.jpg [ 20.46 KiB | Viewed 2517 times ]



Quantity A
Quantity B
Three times the number of units in the perimeter of the figure
The number of square units in the area of the figure



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
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Re: Three times the number of units in the perimeter of the figu [#permalink] New post   28 Jul 2020, 10:34
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First find the length of the missing side. Drop a perpendicular from the vertex connecting the lines with side 13 and the unknown side. The length of the sides are 12 and 9, and by Pythagoras' theorem, the hypotenuse is 15.

With that, the perimeter is 15 + 13 + 9 + 25 = 28 + 34 = 62.
The area is (13*9) + 1/2 (12)(9) = 117 + 54 = 171

62 * 3 = 186 > 171, answer is A.
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Re: Three times the number of units in the perimeter of the figu [#permalink] New post   28 Jul 2020, 10:56
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Quantity A
Quantity B
Three times the number of units in the perimeter of the figure
The number of square units in the area of the figure



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation

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asnwer.png [ 7.9 KiB | Viewed 2509 times ]

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Re: Three times the number of units in the perimeter of the figu [#permalink] New post   23 Mar 2024, 10:38
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Re: Three times the number of units in the perimeter of the figu [#permalink]
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