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[1/4]/[(2/3)-(1-2)/(1/3)]
[#permalink]
12 Jul 2019, 10:55
12 Jul 2019, 10:55
Expert Reply
00:00
Question Stats:
88% (01:48) correct
11% (01:44) wrong based on 99 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
\(\dfrac{ \frac{1}{4}}{\frac{2}{3}-\frac{(1-2)}{\dfrac{1}{3}}} \) |
\(\dfrac{ \frac{1}{3}}{\frac{1}{4}-\frac{(3-4)}{\dfrac{2}{3}}} \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: [1/4]/[(2/3)-(1-2)/(1/3)]
[#permalink]
28 Feb 2024, 05:30
28 Feb 2024, 05:30
1
Quantity A
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{1-2}{\frac{1}{3}}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{-1}{\frac{1}{3}}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{-3}{1}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} + \frac{3}{1}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} + \frac{9}{3}\)
\(\frac{\frac{1}{4}}{\frac{2+9}{3}\)
\(\frac{\frac{1}{4}}{\frac{11}{3}\)
\(\frac{1}{4} \times \frac{3}{11}\)
\(\frac{3}{44}\)
Quantity B
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{3-4}{\frac{2}{3}}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{-1}{\frac{2}{3}}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{-3}{2}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} + \frac{3}{2}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} + \frac{6}{4}\)
\(\frac{\frac{1}{3}}{\frac{1+6}{4}\)
\(\frac{\frac{1}{3}}{\frac{7}{4}\)
\(\frac{1}{3} \times \frac{4}{7}\)
\(\frac{4}{21}\)
Quantity A: \(\frac{3}{44}\) less than \(\frac{1}{11}\) (somewhere around \(\frac{1}{11}\))
Quantity B: \(\frac{4}{21}\) greater than \(\frac{1}{7}\) (somewhere around \(\frac{1}{7}\))
Approx \(\frac{1}{7}\) > Approx \(\frac{1}{11}\)
Quantity B is greater.
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{1-2}{\frac{1}{3}}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{-1}{\frac{1}{3}}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} - \frac{-3}{1}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} + \frac{3}{1}\)
\(\frac{\frac{1}{4}}{\frac{2}{3} + \frac{9}{3}\)
\(\frac{\frac{1}{4}}{\frac{2+9}{3}\)
\(\frac{\frac{1}{4}}{\frac{11}{3}\)
\(\frac{1}{4} \times \frac{3}{11}\)
\(\frac{3}{44}\)
Quantity B
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{3-4}{\frac{2}{3}}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{-1}{\frac{2}{3}}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} - \frac{-3}{2}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} + \frac{3}{2}\)
\(\frac{\frac{1}{3}}{\frac{1}{4} + \frac{6}{4}\)
\(\frac{\frac{1}{3}}{\frac{1+6}{4}\)
\(\frac{\frac{1}{3}}{\frac{7}{4}\)
\(\frac{1}{3} \times \frac{4}{7}\)
\(\frac{4}{21}\)
Quantity A: \(\frac{3}{44}\) less than \(\frac{1}{11}\) (somewhere around \(\frac{1}{11}\))
Quantity B: \(\frac{4}{21}\) greater than \(\frac{1}{7}\) (somewhere around \(\frac{1}{7}\))
Approx \(\frac{1}{7}\) > Approx \(\frac{1}{11}\)
Quantity B is greater.
General Discussion
Re: [1/4]/[(2/3)-(1-2)/(1/3)]
[#permalink]
19 Jul 2019, 21:09
19 Jul 2019, 21:09
3
Quantity A: (1/4)/(2/3+3)=(1/4)/(11/3)=1/4*3/11=3/44=0.068
Quantity B: (1/3)/(1/4-(3-4)/(2/3))= (1/3)/(1/4+1/(2/3))=(1/3)/(1/4+3/2)=(1/3)/((1+6)/4)=1/3*4/7=4/21=0.19
Quantity B: (1/3)/(1/4-(3-4)/(2/3))= (1/3)/(1/4+1/(2/3))=(1/3)/(1/4+3/2)=(1/3)/((1+6)/4)=1/3*4/7=4/21=0.19
